shell command

[Peter Ronai]

zdravim
potrebujem v skripte dostat do premennej meno suboru bez pripony a
posledneho znaku v mene
chcel som to riesit takto ale nefunguje to

name=$(basename $file | cut -d . -f 1 | cut -c 1-$(($(echo $(xargs) | wc
-c) - 2)))

mohli by ste ma niekto nakopnut spravnym smerom pliz?

dz


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