int order by asc, ale nula na konci

[Zdeněk Böhm]

> mysql> select * from pokus order by  (1/(id+1))>=1,id ;
> +-------+---------+
> | id    | name    |
> +-------+---------+
> |     1 | test1   |
> |     3 | test3   |
> |     5 | test5   |
> |     7 | test7   |
> | 30000 | test334 |
> |     0 | test0   |
> |     0 | test0   |
> +-------+---------+

tak to cumim! To je presne ono a pritom je to tak neuveritelne jednoduchy!
hned jsem to i vyzkousel.

Diky Zdenek

P.S. Davide, kdy udelame dalsi seslost brnenskych linux useru?